AQA A Level Physics Paper 2 2019 Mark Scheme

AQA A Level Physics Paper 2 2019 Mark Scheme. MARK SCHEME – A-LEVEL PHYSICS – 7408/2 – JUNE 2019 4 Question Answers Additional Comments/Guidance Mark ID details 01.1 Total energy supplied (= Pt) = 12  890 = 10 680 (J) 1 Heat energy to evaporate nitrogen at its boiling point (= ml) = 0.05  2.0  105 = 10 000 (J) 2 (Use of

AQA A Level Physics Paper 2 2019 Mark Scheme. MARK SCHEME – A-LEVEL PHYSICS – 7408/2 – JUNE 2019 4 Question Answers Additional Comments/Guidance Mark ID details 01.1 Total energy supplied (= Pt) = 12  890 = 10 680 (J) 1 Heat energy to evaporate nitrogen at its boiling point (= ml) = 0.05  2.0  105 = 10 000 (J) 2 (Use of

AQA A Level Physics Paper 2 2019 Mark Scheme. MARK SCHEME – A-LEVEL PHYSICS – 7408/2 – JUNE 2019 4 Question Answers Additional Comments/Guidance Mark ID details 01.1 Total energy supplied (= Pt) = 12  890 = 10 680 (J) 1 Heat energy to evaporate nitrogen at its boiling point (= ml) = 0.05  2.0  105 = 10 000 (J) 2 (Use of

AQA A Level Physics Paper 2 2019 Mark Scheme.MARK SCHEME – A-LEVEL PHYSICS – 7408/2 – JUNE 2019 4 Question Answers Additional Comments/Guidance Mark ID details 01.1 Total energy supplied (= Pt) = 12  890 = 10 680 (J) 1 Heat energy to evaporate nitrogen at its boiling point (= ml) = 0.05  2.0  105 = 10 000 (J) 2 (Use of